计算数学表达式2x/(3b+2a)的值。用C语言。求大神啊、

用双栈求表达式2+4/2-2*1的值，要求用c语言vc++6.0编写。求大神学霸帮忙。~

#include #include using namespace std;char symbol[7] = {'+', '-', '*', '/', '(', ')', '#'};int in[7] = {3, 3, 5, 5, 1, 6, 0};int out[7] = {2, 2, 4, 4, 6, 1, 0};int get(char c){switch(c){case '+':return 0;case '-':return 1;case '*':return 2;case '/':return 3;case '(':return 4;case ')':return 5;case '#':return 6;default: return 6;}} char precede(char c1, char c2){int i1 = get(c1);int i2 = get(c2);if(in[i1] > out[i2]){return '>';}else if(in[i1] data; stack oper; oper.push(get('#'));int sum = 0;int flag = 1; int a, theta, b;if(!('+' == *exp || '-' == *exp || '(' == *exp || isdigit(*exp))){cout ' :b = data.top();data.pop();a = data.top();data.pop();theta = oper.top();oper.pop();data.push(figure(a, theta, b));break;case '<' :oper.push(get(*exp));if(*exp){exp++;}break;case '=' :oper.pop();if(*exp){exp++;}break;}}index = oper.top();}return data.top();}int main(){cout << EvaluateExpression("2+4/2-2*1") << endl;system("pause");return 0;}

#include "stdio.h"#include "math.h"double fact(int n) //求n的阶乘，用double的目的是为了提高表示数的范围{ double sum=1.0; int i; for(i=1;i<=n;i++) sum*=i; return sum;}int main(){ int i,n; double sum=0,item,x; printf("请输入n的值:"); scanf("%d",&n); printf("请输入x的值:"); scanf("%lf",&x); for(i=1;i<=n;i++) { item=pow(x,2*i-1)/fact(2*i); //每一项的值 sum+=item; // 各项值加到一起 } printf("s=x/2!+x^3/4!+....+x^(2n-1)/(2n)!=%lf
",sum);}

#include <stdio.h>
void main()
{
double x, a, b, y;
scanf("%lf,%lf,%lf", &x, &a, &b);
y = 2 * x / (3 * b + 2 * a);
printf("%lf", y);
}

祝你好运~_~

#include<stdio.h>
void main()
{
float x,a,b,y;
scanf("%d%d%d",&x,&a,&b);
y=2*x/(3*b+2*a);
printf("%f",y);
}

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计算数学表达式2x/(3b+2a)的值。用C语言。求大神啊、视频