在线求助初中数学题目、谢谢呐

在线求助大神~

在线求助大神现在是没有神鬼是迷信的说法是不成立的

你的第一题看不懂
什么是
由程序中声明差赋值三个整数的初值?
package tw.com.foxcavity.ks.wangjun.baidu;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

import tw.com.foxcavity.ks.wangjun.baidu.exception.InValideParametersException;

public class test {

private int[] zhaoling;


public test() {
zhaoling = new int[6];
zhaoling[0] = 0;//500
zhaoling[1] = 0;//100
zhaoling[2] = 0;//50
zhaoling[3] = 0;//10
zhaoling[4] = 0;//5
zhaoling[5] = 0;//1

}

/**
* 检查输入的参数是否符合格式
* @param str
* @return
* @throws InValideParametersException
*/
public String[] checkPara(String str) throws InValideParametersException {

String[] paras = str.split(";");
if(paras.length == 0)
throw new InValideParametersException("请输入正确的参数!
" +
"userage:;");
return paras;
}

/**
* 获得的输入参数
* @return
* @throws IOException
* @throws InValideParametersException
*/
public String getSystemIn() throws IOException,InValideParametersException {
System.out.println("请输入参数:");
BufferedReader br;
String str = "";
try {
br = new BufferedReader(new InputStreamReader(System.in));
if (br == null) {
throw new InValideParametersException("请输入参数!
" +
"userage:;");
}
str = br.readLine();
}catch (IOException ex) {
ex.printStackTrace();
}
return str;

}
/**
* 计算零钱格式
* @param str
*/
public int cal(int money) {
int div = 0;
int mod = 0;
if(money > 500){
div = money / 500;
mod = money % 500;
zhaoling[0] = div;

}else if(money > 100){
div = money / 100;
mod = money % 100;
zhaoling[1] = div;

}else if(money > 50){
div = money / 50;
mod = money % 50;
zhaoling[2] = div;

}else if(money > 10){
div = money / 10;
mod = money % 10;
zhaoling[3] = div;

}else if(money > 5){
div = money / 5;
mod = money % 5;
zhaoling[4] = div;

}else{
div = money / 1;
mod = money % 1;
zhaoling[5] = div;

}
return mod;
}

public String showMoney() {

String str = String.valueOf(zhaoling[0]) + String.valueOf(zhaoling[1]) + String.valueOf(zhaoling[2]) +
String.valueOf(zhaoling[3]) + String.valueOf(zhaoling[4]) + String.valueOf(zhaoling[5]);
return str;

}

/**
* @param args
* @throws IOException
*/
public static void main(String[] args) {
test t = new test();
try{
String str = t.getSystemIn();
String[] paras = t.checkPara(str);
int a = Integer.parseInt(paras[0]);//所应付款的金额
int b = Integer.parseInt(paras[1]);//实际交给店员的金额
int c = b - a;//零钱
while(c > 0){
c = t.cal(c);
}
System.out.println(t.showMoney());
}catch(IOException e){
System.out.println(e.getMessage());
}catch(InValideParametersException ie){
System.out.println(ie.getMessage());
}



}

}


package tw.com.foxcavity.ks.wangjun.baidu.exception;

public class InValideParametersException extends Exception {
public InValideParametersException(String msg) {
super(msg);
}


}

1 (a-b)/(a+b)+(a+b)/(b-a)=(a-b)(b-a)/(a+b)(b-a)+(a+b)(a+b)/(b-a)(a+b)

=(-a^2+2ab-b^2+a^2+2ab+b^2)/(b^2-a^2)=4ab/(b^2-a^2)

2 -6a^3b^2-3a^2b^2-12a^2b^3=-3a^2b^2(2a+1+4b)

3 (x+2)^2-(y+2)^2=4 x=-y => x^2=(-y)^2=y^2

x^2+4x+4-(x^2-4x+4)=8x=4 ==> x=1/2 y=-1/2

4 y=kx 4=(-2)*k => k=-2 ==> y=-2x

5 x=0时,y=-1-m

由方程可知 : x1+x2=2(m-1) x1*x2=-1-m

oc(ob-oa)=2oa*ob ==> y(x1+x2)=2*(-x1*x2)

==> (1+m)*2*(m-1)=2*(1+m) 解出 m=2

==> y=x^2-2x-3

6 |1-根号2|+根号5-2根号6=根号2-1+根号5-2根号6 （不明白这题什么意思）

7 2x-y-m=0 ==> x=2/3m

x+y-m=0 y=1/3m

方程组有正解，m>0

8 ax^2+bx+c=0 二次项系数为a , 一次项系数为b, 常数项系数为c

a+c=b 当x=-1时，a*(-1)^2+b*(-1)+c=a-b+c=0 恒成立

9 y=x^2-mx+3 ==> a+b=m ab=3 a,b为同号

AB=|a-b| ==> AB^2=(a-b)^2= (a+b)^2-4ab ==>

2^2=m^2-12 ==> m=4或m=-4

为了你这10分，真不容易啊！！！！！

我。。。越发的体会到耳麦的重要性。。。
为了分数。。我得慢慢打。。原始(a-b)/(a+b)+(a+b)/(b-a)=(a-b)(b-a)/(a+b)(b-a)+(a+b)(a+b)/(b-a)(a+b)
=(-a^2+2ab-b^2+a^2+2ab+b^2)/(b^2-a^2)=4ab/(b^2-a^2)

2 -6a^3b^2-3a^2b^2-12a^2b^3=-3a^2b^2(2a+1+4b)

3 (x+2)^2-(y+2)^2=4 x=-y => x^2=(-y)^2=y^2

x^2+4x+4-(x^2-4x+4)=8x=4 ==> x=1/2 y=-1/2

4 y=kx 4=(-2)*k => k=-2 ==> y=-2x

5 x=0时,y=-1-m

由方程可知 : x1+x2=2(m-1) x1*x2=-1-m

oc(ob-oa)=2oa*ob ==> y(x1+x2)=2*(-x1*x2)

==> (1+m)*2*(m-1)=2*(1+m) 解出 m=2

==> y=x^2-2x-3

6 |1-根号2|+根号5-2根号6=根号2-1+根号5-2根号6 是这样子的么？我不是太清楚你的意思。。好模糊

7 2x-y-m=0 ==> x=2/3m

x+y-m=0 y=1/3m

方程组有正解，m>0

8 ax^2+bx+c=0 二次项系数为a , 一次项系数为b, 常数项系数为c

a+c=b 当x=-1时，a*(-1)^2+b*(-1)+c=a-b+c=0 恒成立

9 y=x^2-mx+3 ==> a+b=m ab=3 a,b为同号

AB=|a-b| ==> AB^2=(a-b)^2= (a+b)^2-4ab ==>

2^2=m^2-12 ==> m=4或m=-4

---

在线求助初中数学题目、谢谢呐视频