利用python算闰年

怎么用python语言判断闰年~

闰年 : 四年一闰，百年不闰，四百年再闰。
例如，2000年是闰年，2100年则是平年
year = int(input("输入一个年份: "))if (year % 4) == 0: if (year % 100) == 0: if (year % 400) == 0: print("{0} 是闰年".format(year)) # 整百年能被400整除的是闰年 else: print("{0} 不是闰年".format(year)) else: print("{0} 是闰年".format(year)) # 非整百年能被4整除的为闰年else: print("{0} 不是闰年".format(year))

#include
#define ISPRIME(x) (x)%400==0||(x)%4==0&&(x)%100!=0
int main()
{
int a,b,cnt;
while(scanf("%d,%d",&a,&b)==2)
{
for(cnt=0;a<=b;++a)
{
if(ISPRIME(a))
{
printf("%-7d",a);
if(++cnt%5==0)
printf("
");
}
}
}
return 0;
}

start = int(raw_input('Starting year : '));
stop = int(raw_input('Ending year : '));
leap = 0;

for year in range(start, stop+1) :
if (year%4 == 0 and (year%100 != 0 or year%400 == 0) ) :
print year, "is leap year";
leap += 1;
else :
print year, "is not a leap year"
print "Total number of leap years : ", leap

#加入了排错

#python 2.5

try:
begin = int(raw_input("Starting year : "))
end = int(raw_input("Ending year : "))
if begin > end:
raise Exception
except Exception:
print "Bad input!"
exit()

total = 0
for year in xrange(begin, end):
if (year%4 == 0 and year%100 != 0) or year%400 == 0:
print year, "is a leap year"
total += 1
else:
print year, "is not a leap year"
print "Total number of leap years :", total

#貌似楼上C的语法和python的搞混了...

def total_days(start_year, end_year):
    T = 0
    for k1 in range(start_year, end_year):
        if (k1 % 4) == 0 and (k1 % 100) != 0 or (k1 % 400) == 0:
            T+=1
            print("ruan nian " +str(k1))
        else:
            print(str(k1)+"bushi ruinian")
    print(str（T）+"run nian you duoshaotian ")
    return T*366+(end_year-start_year-T)*365

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